You do 2.2 kJ of work pushing a trunk at a constant speed 3.1 m along a ramp inclined upward at 22 degrees. What is the frictional coefficient between the trunk and the ramp?
W = F*d
Ff = μmg * cos(θ)
Fg = mg * sin(θ)
The Attempt at a Solution
To find the force exerted on the trunk up the ramp, I divide 2200 J by 3.1 m to get 710 N.
Since the trunk is moving at a constant speed, the forces pulling the trunk down the ramp must equal the forces pushing it up the ramp.
710 = Fg + Ff
710 = mg*sin(22) + μmg*cos(22)
710 = mg( sin(22) + μcos(22) )
...Aaaaand this is where I get stuck. I feel like there is some obvious way to either solve for or get rid of the mass that I'm just not seeing. My book gives 0.6 as the answer.
Any help would be greatly appreciated.