Finding the coefficient of friction

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The coefficient of friction between a 65-kilogram chair and the floor is calculated using the formula μ = Ffr/Fn. With a frictional force (Ffr) of 220 Newtons and a normal force (Fn) of 637 Newtons, the coefficient of friction (μ) is approximately 0.345. The calculations provided are correct, confirming the accuracy of the result. The discussion highlights the importance of understanding the relationship between force, mass, and friction in physics. Overall, the method for determining the coefficient of friction is validated.
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What is the coefficient of friction between a 65-kilogram chair and a floor if the chair can be pushed at constant speed with a force of 220 Newtons?

My attempt:
Given:
m=65 kg Ffr (force of friction)=220 N
w=mg=(65)(9.8)=637 Fn=637 N
μ=?
μ=Ffr/Fn
μ=220/637
μ≈0.345

Is this right? I honestly don't know what I'm doing so if anyone can help me it would be much appreciated. Thanks!
 
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