Finding the coefficient of friction

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SUMMARY

The coefficient of friction between a 65-kilogram chair and a floor is calculated using the formula μ = Ffr / Fn, where Ffr is the force of friction and Fn is the normal force. In this case, with a force of 220 Newtons required to push the chair at constant speed, the normal force is 637 Newtons. The resulting coefficient of friction (μ) is approximately 0.345, confirming the calculations provided in the discussion. The methodology and calculations are accurate and valid.

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  • Ability to perform calculations involving mass and weight
  • Familiarity with the concept of normal force
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theeggwoman
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What is the coefficient of friction between a 65-kilogram chair and a floor if the chair can be pushed at constant speed with a force of 220 Newtons?

My attempt:
Given:
m=65 kg Ffr (force of friction)=220 N
w=mg=(65)(9.8)=637 Fn=637 N
μ=?
μ=Ffr/Fn
μ=220/637
μ≈0.345

Is this right? I honestly don't know what I'm doing so if anyone can help me it would be much appreciated. Thanks!
 
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