theeggwoman
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What is the coefficient of friction between a 65-kilogram chair and a floor if the chair can be pushed at constant speed with a force of 220 Newtons?
My attempt:
Given:
m=65 kg Ffr (force of friction)=220 N
w=mg=(65)(9.8)=637 Fn=637 N
μ=?
μ=Ffr/Fn
μ=220/637
μ≈0.345
Is this right? I honestly don't know what I'm doing so if anyone can help me it would be much appreciated. Thanks!
My attempt:
Given:
m=65 kg Ffr (force of friction)=220 N
w=mg=(65)(9.8)=637 Fn=637 N
μ=?
μ=Ffr/Fn
μ=220/637
μ≈0.345
Is this right? I honestly don't know what I'm doing so if anyone can help me it would be much appreciated. Thanks!