Finding the curl and divergence

  • #1
264
0

Homework Statement



[tex]\vec{F}(x,y,z) = x^2y\vec{i} + y^2z^3\vec{j} + xyz\vec{k}[/tex]

Homework Equations



The Attempt at a Solution



I got:

Curl: [tex] (xz - 3y^2z^2)\vec{i} + (-yz)\vec{j} + (-x^2)\vec{k}[/tex]
Div: [tex] 2xy + 2yz^3 + xy[/tex]

Are these right?
 
Physics news on Phys.org
  • #2
duki said:
[
Curl: [tex] (xz - 3y^2z^2)\vec{i} + (-yz)\vec{j} + (-x^2)\vec{k}[/tex]
Div: [tex] 2xy + 2yz^3 + xy[/tex]

Are these right?

Looks good to me (although I would write the divergence as [itex] 3xy + 2yz^3 [/itex]:wink:)
 
  • #3
Awesomes. Thanks
 

Suggested for: Finding the curl and divergence

Replies
1
Views
618
Replies
4
Views
452
Replies
8
Views
742
Replies
15
Views
819
Replies
14
Views
1K
Replies
2
Views
1K
Back
Top