Finding the Direction Vector of a Line: Tips and Tricks

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Homework Help Overview

The original poster seeks to find the direction vector of a line represented by the equation ax + by + c = 0. The discussion revolves around understanding the relationship between this equation and the concept of direction vectors in the context of lines.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Some participants clarify that the original equation was misidentified as that of a plane, prompting a correction to the appropriate line equation. Others suggest that the slope of the line can be used to determine a direction vector.

Discussion Status

The discussion is active, with participants engaging in clarifying the original question and exploring the implications of the corrected equation. There is a recognition of the relationship between the slope and direction vectors, although no consensus has been reached on the specifics of the solution.

Contextual Notes

Participants note the potential confusion arising from the initial equation and its implications for identifying the correct geometric representation. There is also an acknowledgment of the time elapsed since the original post, which may affect engagement levels.

Nevermore
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How would I find the direction vector of a line given in the form ax + by + cz +d =0?

Thankyou.
 
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I see an equation of a plane, not a line.
 
Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...
 
Nevermore said:
Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...
For a line, (1,m) is always a directional vector where m is the slope. Can you find the slope?
 
Yeah - I thought it would be something simple like that. Thanks for your help.
 
You're welcome :smile:
 
Thanks for asking that Q, it helped me too
 
I don't think there's a need to thank someone who started a thread two years ago and have not posted since.
 
LORL... Thanks for pointing that out. ( At least you still logon)
 

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