Finding The Divergence Of A Vector Field

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The discussion focuses on finding the divergence of the vector field < ex2 - 2xy, sin(y^2), 3yz - 2x>. The correct method involves calculating the divergence using the formula ∇ dot F. The initial calculation yielded an incorrect result, with a discrepancy in the last term, where one participant obtained '3y' instead of the correct 'y' as indicated by Wolfram Alpha. The error was identified as neglecting to differentiate the term -2xy in the first component. The clarification led to agreement on the correct answer, emphasizing the importance of careful differentiation in vector calculus.
Baumer8993
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Homework Statement


Find The Divergence Of The Vector Field:
< ex2 -2xy, sin(y^2), 3yz-2x>


Homework Equations


I know that divergence is ∇ dot F.


The Attempt at a Solution


When I did it by hand I got
2xex2 + 2ycos(y2) + 3y

However wolfram alpha says it should be

2xex2 + 2ycos(y^2) + y

The difference is the last y. So who is right? This is for a divergence theorem problem, but I do not have an answer key.
 
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When you worked out the first term, you forgot to differentiate the -2xy.
If you include this, your answer will agree with Wolfram.
 
Hi Baumer8993! :smile:

- 2xy ? :wink:
 
Oh wow, thank you for the help!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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