- #1
thursdaytbs
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I have a positive and a negative charged plate running parallel to one another. To find the Electric Field to the left of the plates, I say:
E dot dA = Qenclosed / permittivity
Then E times 2pi(r) = Qenclosed / Permittivity
then E = Qenclosed / 2pi(r) x Permittivity
and since Qenclosed to the left and right of the parallel plates is zero, E = zero?
And for in between the two plates I can say the charge enclosed is 2pi(r)^2 times the charge enclosed by that area? divided by 2pi(r) x Permittivity?
I'm a little bit lost as to how to explain in detail how to solve for the Electric Field in between oppositely charged parallel plates. Any help? Thanks.
E dot dA = Qenclosed / permittivity
Then E times 2pi(r) = Qenclosed / Permittivity
then E = Qenclosed / 2pi(r) x Permittivity
and since Qenclosed to the left and right of the parallel plates is zero, E = zero?
And for in between the two plates I can say the charge enclosed is 2pi(r)^2 times the charge enclosed by that area? divided by 2pi(r) x Permittivity?
I'm a little bit lost as to how to explain in detail how to solve for the Electric Field in between oppositely charged parallel plates. Any help? Thanks.