I have a positive and a negative charged plate running parallel to one another. To find the Electric Field to the left of the plates, I say: E dot dA = Qenclosed / permittivity Then E times 2pi(r) = Qenclosed / Permittivity then E = Qenclosed / 2pi(r) x Permittivity and since Qenclosed to the left and right of the parallel plates is zero, E = zero? And for in between the two plates I can say the charge enclosed is 2pi(r)^2 times the charge enclosed by that area? divided by 2pi(r) x Permittivity? I'm a little bit lost as to how to explain in detail how to solve for the Electric Field in between oppositely charged parallel plates. Any help? Thanks.