I have a positive and a negative charged plate running parallel to one another. To find the Electric Field to the left of the plates, I say:(adsbygoogle = window.adsbygoogle || []).push({});

E dot dA = Qenclosed / permittivity

Then E times 2pi(r) = Qenclosed / Permittivity

then E = Qenclosed / 2pi(r) x Permittivity

and since Qenclosed to the left and right of the parallel plates is zero, E = zero?

And for in between the two plates I can say the charge enclosed is 2pi(r)^2 times the charge enclosed by that area? divided by 2pi(r) x Permittivity?

I'm a little bit lost as to how to explain in detail how to solve for the Electric Field in between oppositely charged parallel plates. Any help? Thanks.

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# Homework Help: Finding the E-Field between parallel plates

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