Two equal positive charges are held fixed and separated by distance D. Find the electric field(adsbygoogle = window.adsbygoogle || []).push({});

vector along their perpendicular bisector. Then find the position relative to their center where

the field is a maximum.

so i started with symmetry and principle of superposition

and got to this answer

E = (1/(4πε))*q*D i^/( y^2 + (D^2)/4)^(3/2)

y stand for the distance from the field to the origin

is this equation the right answer for the first question? Also for the second question what changes when E is a maximum?

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# Homework Help: Finding the electric field vector along the bisector

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