How to find vectors and bisectors of an electric field

[SirChris93]

<Moderator's note: User has been warned not to remove the template, and upload images instead of linking to an external site.>

I'm very lost here, I don't know where to begin. My instructor is little help, the notes he gives are not even useful, and I cannot find anything in the book.We were given 4 graphs about electric charges that we need to find the vectors on and one of them include drawing a bisector. If I can get pointed in the right direction with at least the first segment, I'm sure I would be fine with the others.What the assignment says:

Segment A:

https://imgur.com/a/PHS2H

1) Neatly draw the bisector of the arc on the diagram2) Neatly draw the vector along the bisector that represents the Electric Field produced by the arcSegment B:

https://imgur.com/a/W390A
1)Neatly sketch the vector that represents the EF produced by segment B.

Attempt at solution:

For part A, I’m pretty sure the bisector would go through quadrant 2 and 3, but I’m not sure.

 

[BvU]

Hello,

Please post in introductory and use the template.

And I hate imgur flashing around on my screen. Just copy/paste the images in your post (or upload them).

What the assignment says:

Does it say anything else ? Like: there is a charge ?

 

[BvU]

'Bisector of the arc' is pretty clear. Why do you think quadrant 2 and 3 (in which notation is that ?) ?

 

[SirChris93]

'Bisector of the arc' is pretty clear. Why do you think quadrant 2 and 3 (in which notation is that ?) ?

Because, it looks like it is going in the negative direction.

 

[BvU]

The arc has an opening in a particular quadrant. So the bisector will have to divide the arc and the opening into equal pieces...

 

[BvU]

By the way, in my book quadrant 2 and 3 are the half-plane x < 0

 

[SirChris93]

By the way, in my book quadrant 2 and 3 are the half-plane x < 0

Then would the bisector be opposite?

 

[BvU]

Opposite with respect to what, exactly ?

 

[SirChris93]

Then would the bisector be opposite?

Opposite of what I though.

So I think the vectors would be in those two quadrants, but the bisector would be in Q1

 

[BvU]

Opposite of what I though.

General rule: Don't let us guess what you think. Type it out.

the bisector would be in Q1

Not the complete answer.

bisector of the arc

the entire arc, that is.

Can you please post the Complete problem statement ?