Finding the Initial Rate of Gas Leakage from a Small Hole in a Cubic Container

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SUMMARY

The discussion focuses on calculating the initial rate of gas leakage from a cubic container with a small hole. The relevant formula used is \( p = \frac{\rho c^2}{3} \), where \( p \) is pressure, \( \rho \) is gas density, and \( c \) represents the speed of gas molecules. The initial leakage rate is proposed as \( \frac{av}{3} \), where \( a \) is the cross-sectional area of the hole and \( v \) is the molecular speed. However, it is emphasized that the pressure difference between the inside and outside of the container must be considered for an accurate calculation.

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Homework Statement


A cubic container with sidelength l has a small hole with cross sectional area a (a<<l). The gas has density ρ and pressure P. Find the initial rate of gas leakage given that the outside pressure is 0.


Homework Equations



The question mentions the formula p=ρc2/3 so I know I have to use this.

The Attempt at a Solution



Assume that 1/3 of the particles are moving in a direction towards the hole. Any molecule in a cylinder of base a and length c will leave the hole in one second so is the leakage rate av/3, and then I can substitute out c with the formula? Is this the correct answer?
 
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Any molecule in a cylinder of base a and length c will leave the hole in one second
Not bad - but your result does not appear to take the pressure difference into account.

I'd have wanted to see that explicit - can you explain what your equations mean and how you are using them.
I suspect you have it right, but cannot tell exactly from what you've written down so far.
 
Last edited:

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