Finding the Interval of Convergence for a Series

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Homework Help Overview

The discussion revolves around finding the interval of convergence for a series, specifically focusing on the values of x for which the series converges. The original poster expresses confusion regarding the process after determining the radius of convergence.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the radius of convergence and its implications for determining the interval of convergence. There are attempts to clarify the correct interval and questions about the transformation of inequalities related to convergence.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning their reasoning. Some guidance has been provided, particularly regarding the interpretation of absolute values in inequalities, but no consensus has been reached on the correct interval.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also a mention of confusion regarding the application of convergence tests and the correct interpretation of results.

mr_coffee
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Hello everyone, I'm confused (as usual). I think i found the radius of convergence but then what do i do to find the interval on which it converges?

The directions says:
Find all the values of x such that the given series would converge.
http://cwcsrv11.cwc.psu.edu/webwork2_files/tmp/equations/70/aaf16ffcdb10d6976585856b5dafca1.png
The series is convergent
from x = , left end included (enter Y or N):
to x = , right end included (enter Y or N):

Here is my work:
http://img90.imageshack.us/img90/6637/lastscan5ox.jpg


Any help would be great! thankss!
 
Last edited by a moderator:
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OKay i had to of messed up finding the radius of convergence. I looked at a tutoiral and it should be right...
I got
(-7,7); for the interval, which was wrong though. Can you see where i screwed it up? it should be open brackets i got that part right

Okay i did it again, and i tried (-14,14), now i have 75% of the question rgiht, so either -14 is wrong or 14 is wrong but i don't see how u can get any other number then that.
if u have
|(x-7)/7| < 1

and
|(x-7)/7| > 1
 
Last edited:
Why did \left|\frac{x-7}{7}\right|&lt; 1 become x-7< 7??
Shouldn't it be |x-7|< 7? And doesn't that mean that -7< x- 7< 7?
So that 0< x- 7< 14?
 
Thanks Ivey ur the man! i forgot all about that rule!
w00t.
 

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