Finding the Longitudinal Force: A Scientific Approach

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SUMMARY

The discussion focuses on calculating the longitudinal force exerted on a charged thread placed parallel to a conductive strip with a uniform surface charge density (σ). The participant derives the electric field (E) generated by the strip, concluding that E = σ/3ε0 and subsequently finds the force (F') on the thread as F' = Q'σ/3ε0. Participants raise concerns about the interpretation of "longitudinal force," the contradiction in the strip's conductive nature and uniform charge density, and the accuracy of the integral used in the calculations.

PREREQUISITES
  • Understanding of electrostatics, specifically electric fields generated by charged objects.
  • Familiarity with calculus, particularly integration techniques.
  • Knowledge of the principles of symmetry in electric fields.
  • Basic concepts of conductive materials and charge distribution.
NEXT STEPS
  • Review the derivation of electric fields from continuous charge distributions.
  • Study the implications of charge density on conductive materials.
  • Learn about the application of integrals in calculating electric fields and forces.
  • Explore the differences between longitudinal and normal forces in electrostatics.
USEFUL FOR

This discussion is beneficial for physics students, educators, and professionals involved in electrostatics, particularly those interested in force calculations related to charged objects and conductive materials.

cdummie
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Homework Statement


Very long thread, with constant longitudinal charge Q' is placed in a vacuum parallel to a very long conductive strip, whose width is a. thread is placed in the middle of the strip and it's a/2 away from it, if the surface density of charge of the strip is σ, find the longitudinal force to a thread.

Homework Equations

The Attempt at a Solution



since F=Q*E it means that F'=Q'*E so i have to find E to find F, i could think of strip as a very big number of thin lines of charge, then, knowing the value of E for every single line i could sum up all of the contributions from one to another end of the strip. Since the E of the single line is (it's dE for the whole system):
firstEquation.png

where d is distance from one charged line to a thread.

Because of the symmetry, x component of the vector E will be zero, which means there's only y component and it's
dEy=(σ*dl*cosθ)/(2πε0d)

Since dl, d, and cosθ are unknowns i need to express them with some values i know, since cosθ*dl=r*dθ it means that cosθ/r=dθ/dl i have:

dE=(σ*dl*dθ)/(2πε0dl)

dE=(σ*dθ)/(2πε0)

which means i have to integrate over angle,
i have the distance form middle of strip to a thread and it's a/2 and it's in the middle so i have the distance to both ends form middle equal a/2, which means i could find distance form first (and last) thin line using Pythagoras theorem and it's sqrt(2)*a/2, now i can easy find the angle I'm looking for since sinθ equals opposite over hypotenuse it's sqrt(2)/2 and it means that angle is π/3 so i have integral form -π/3 to π/3 for this expression
dE=(σ*dθ)/(2πε0)

when i solve it i get

E=σ/3ε0
and F'=Q'*σ/3ε0

Now, my question is. Is this good approach, because I'm not sure is this correct?
 
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A number of things I'm not following here.
Wouldn't longitudinal force mean force parallel to the thread? But I see no reason why there would be such a force. On the other hand, if it means the force normal to the strip then that will be proportional to the length, which is not given. Maybe I have the wrong picture.

It says the strip is conducting, but then indicates it has a uniform charge density. That's contradictory.

The equation you show for the field has it inversely proportional to the distance. Not inverse square?

I can't tell if your integral is right without more detail. I believe it should involve a ##\cos^3## term.
 

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