- #1
Touran Khan
- 16
- 2
Homework Statement
Homework Equations
F = ma
The Attempt at a Solution
My value for P does not make any sense. Why is this so?
Finding the magnitude of force P
- Thread starter Touran Khan
- Start date
-
- Tags
- Force Forces Magnitude Second law
Click For Summary
Homework Help Overview
The discussion revolves around finding the magnitude of a force, denoted as P, in a physics problem involving forces and equilibrium. The subject area includes concepts of mechanics, specifically the analysis of vertical and horizontal forces.
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants discuss the potential oversight of vertical forces, particularly the normal force, in the original calculations. There is an exploration of how these forces interact and affect the value of P. Questions arise regarding the definition and value of the normal force in the context of the problem.
Discussion Status
Participants have identified a possible error in the original poster's approach related to the normal force. Some guidance has been offered regarding the use of a variable for the normal force until further calculations can clarify its value. Multiple interpretations of the term "reaction force" are being explored, with some participants suggesting it refers to the normal force.
Contextual Notes
There is an indication that the original poster may be working under specific homework constraints, as they express uncertainty about the values of certain forces and their implications in the equations being used.
F = ma
My value for P does not make any sense. Why is this so?
- #2
TomHart
- 684
- 172
I think you may have forgotten one of the vertical forces.
- #3
Touran Khan
- 16
- 2
TomHart said:
Yeah, I'm almost certain that's the issue. I think it's the normal force, but what is the value of that force in this case?
- #4
TomHart
- 684
- 172
Yes, you forgot the normal force when you summed the vertical forces. But I don't know what the value of that force is. You will just have to use a variable, FN, until you solve the equations and find its value.
- #5
Touran Khan
- 16
- 2
TomHart said:
Oh right, my bad. So for vertical forces my equation ends up being Psin10 - 70cos45 + Fn = 0. From the horizontal forces equation I calculated P to be 57.369...
Then, Fn = 39.535...
To sum it up, P = 57.4 and Fn = 39.54. These values satisfy both equations, though do you have any idea what reaction force they are referring to?
- #6
TomHart
- 684
- 172
That looks right. I'm not sure but "reaction force", probably means the normal force.
- #7
Touran Khan
- 16
- 2
TomHart said:
Alright that's what I was thinking as well, no idea what else it could be. Thanks for the help.
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