A ball is launched as a projectile with initial speed v at an angle theta above the horizontal. Using conservation of energy, find the maximum height h_max of the ball's flight. Express your answer in terms of v, g, and theta. My energy equation is as follows: 0.5m(v^2)cos(theta) +0.5m(v^2)sin(theta) = 0.5m(v^2)cos(theta) + mgh_max v^2cos(theta) + v^2sin(theta) = 2gh_max + v^2cos(theta) h_max = (v^2sin(theta))/2g This isn't right, somehow. I know that the only velocity at max height is in the x-direction, so max height should be a sine function, right? Did I forget to include something in my energy equation?