Finding the Maximum Electric Field of a Charged Ring

Click For Summary
SUMMARY

The discussion centers on determining the maximum electric field generated by a charged ring with a radius of 20.6 cm and a total charge of 12 nC. The electric field at a perpendicular distance z from the center of the ring is described by the formula Ering = (1/4 pi ε₀) (zQ/(z²+R²)^(3/2)). Participants analyze the behavior of the electric field as distance changes, noting that it starts at zero, increases, and then decreases, indicating a maximum field at a specific distance. The differentiation of the electric field function E(x) = [kQ/(x² + r²)]*[x/sqrt(x² + r²)] is necessary to find this maximum.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with calculus, specifically differentiation
  • Knowledge of the geometry of charged rings
  • Concept of electric field components and their vector nature
NEXT STEPS
  • Learn how to differentiate functions involving multiple variables
  • Study the behavior of electric fields from different charge distributions
  • Explore the application of the maximum value theorem in calculus
  • Investigate the physical significance of electric field maxima in electrostatics
USEFUL FOR

Students and educators in physics, particularly those studying electromagnetism and electric fields, as well as anyone involved in solving problems related to charged particle systems.

05holtel
Messages
52
Reaction score
0

Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this
 
Physics news on Phys.org
05holtel said:

Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this

Well if the field starts off at zero at x= 0 then increases, and then dies off again, then I think we would look at where dE/dx = 0 as this is where the slope of an E v. x graph would be maximum.

In the equation given, they give you the e-field function of this ring, with Z being your X? Or is Z supposed to be the radius of the ring, or is R the radius of the ring and not the distance from a specific segment of the ring of charge to the point of interest?
 
In others words, r is usually the distance from some charge to some place you are looking for the E field. In the equation you were given, is r the radius of the charged ring, or the distance from the charge to the place of interest..?
 

Similar threads

Replies
4
Views
4K
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 68 ·
3
Replies
68
Views
8K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
9
Views
1K