Finding the Minimum Angle for Motion on an Inclined Plane

  • Thread starter Thread starter physics_freak
  • Start date Start date
  • Tags Tags
    Angle Minimum
Click For Summary
SUMMARY

The minimum angle required for a box with a mass of 45 kg to start moving on an inclined plane is 27 degrees. When the mass is doubled to 90 kg, the minimum angle necessary for motion increases due to the increased gravitational force acting on the box. The frictional force can be calculated using the equation F_friction = mg sin(θ), where θ is the angle of inclination. Therefore, the new angle can be determined by analyzing the relationship between mass and the sine of the angle.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of trigonometry, specifically sine functions
  • Familiarity with the concept of frictional forces
  • Ability to manipulate equations involving mass and angles
NEXT STEPS
  • Calculate the new minimum angle for a 90 kg mass on an inclined plane
  • Explore the effects of different coefficients of friction on motion
  • Study the dynamics of inclined planes in physics
  • Learn about static versus kinetic friction in practical applications
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined planes, as well as educators looking for practical examples of motion and friction.

physics_freak
Messages
5
Reaction score
0

Homework Statement



A box with mass of 45 kg is placed on a flat board. It starts moving when the board is inclined at 27 degrees. If the mass is doubled, what is the minimum angle needed so that it starts moving?

Homework Equations



Frictional force = mgsin[tex]\theta[/tex]

The Attempt at a Solution

 

Attachments

Physics news on Phys.org
physics_freak said:

Homework Statement



A box with mass of 45 kg is placed on a flat board. It starts moving when the board is inclined at 27 degrees. If the mass is doubled, what is the minimum angle needed so that it starts moving?

Homework Equations



Frictional force = mgsin[tex]\theta[/tex]

The Attempt at a Solution

Your (or is it the book's?) solution is correct.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
11
Views
1K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K