Finding the n in stokes theorem.

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Homework Help Overview

The discussion revolves around Stokes' theorem, specifically focusing on determining the normal vector \( n \) for a given vector field \( F \) and a closed curve \( C \) in the xy-plane. The original poster expresses confusion regarding the identification of \( n \) as \( k \) in the context of the right-hand rule.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of the right-hand rule to determine the normal vector based on the orientation of the curve. Questions arise about the implications of different orientations and the interpretation of motion in relation to the normal vector.

Discussion Status

The discussion is ongoing, with participants providing insights into the right-hand rule and its application. There is an exploration of different scenarios regarding the orientation of the normal vector, but no consensus has been reached on the implications of these orientations.

Contextual Notes

Participants note that the textbook explanation of the topic may lack clarity, leading to confusion about the normal vector's determination in relation to Stokes' theorem.

Mdhiggenz
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Homework Statement



Hey guys,

I'm having trouble finding the n in stokes theorem.

For example,

F(x,y,z)= z2i+2xj-y3; C is the circle x2 + y2=1 in the xy-plane with counterclockwise orientation looking down the positive z-axis.

∫∫CurlF*n

I know the curl is -3y2i+2zj+2k

The book found that n=k and just multiplied it out. I don't understand where they got that value.

Thanks


Homework Equations





The Attempt at a Solution

 
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Mdhiggenz said:

Homework Statement



Hey guys,

I'm having trouble finding the n in stokes theorem.

For example,

F(x,y,z)= z2i+2xj-y3; C is the circle x2 + y2=1 in the xy-plane with counterclockwise orientation looking down the positive z-axis.

∫∫CurlF*n

I know the curl is -3y2i+2zj+2k

The book found that n=k and just multiplied it out. I don't understand where they got that value.

Thanks

Imagine grabbing the z axis with your right hand with your thumb pointing up the axis. Are you fingers going counterclockwise when you look down at them. If so, your thumb is pointing the direction of the normal, which in this case is k. It's the "right-hand rule".
 
Thanks for the response, Let's say it was moving in the negative z direction, thus going counterclockwise would it just be -k? Also the book doesn't seem to explain that whole topic very well.
 
Mdhiggenz said:
Thanks for the response, Let's say it was moving in the negative z direction, thus going counterclockwise would it just be -k? Also the book doesn't seem to explain that whole topic very well.

? A particle going in the negative z direction is not going counterclockwise or clockwise. It is going in a straight line.

The right hand rule states that if you have motion around a closed plane curve and you point your right hand fingers along the curve in the direction of motion, your thumb will point in the direction of the corresponding normal to orient the surface for Stokes' theorem.
 

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