Finding the Net Force on a Box on an Inclined Plane

[chiurox]

Homework Statement

A box of mass, m, is on a plane inclined at an angle, q, relative to the horizontal. The coefficient of kinetic friction between the box and the incline is uk, and the body is accelerating down the incline. What is the net force on the body?

The Attempt at a Solution

Well, if the box is accelerating down the incline, the mg(sinTheta) vector of the box must be greater than the Ffriction. But I don't know how to go from there.
I'm guessing it's mg (sin q - uk cos q) but I'm not sure. Could anything clarify for me?

 

[Doc Al]

No need to guess--you're correct. There are only two forces on the box parallel to the incline: the component of gravity and the kinetic friction.

 

[chiurox]

No need to guess--you're correct. There are only two forces on the box parallel to the incline: the component of gravity and the kinetic friction.

Yeah, I just realized now how easy this question is. Thanks for confirming.