Finding the point where the net electric field is zero

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To find the point where the net electric field is zero between a +3 charge and a -1 charge, the electric fields created by both charges must be equal in magnitude and opposite in direction. The relationship can be expressed as E1 = -E2, leading to the equation 3/(r+d)^2 = 1/r^2, where r is the distance from the -1 charge to point P and d is the distance between the two charges. By solving this equation, the exact location of point P can be determined relative to the distance between the charges. The choice of coordinate system does not affect the outcome. This method provides a clear approach to solving the problem.
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Homework Statement


The question wasn't really written down. It was a question asked after an explanation, and it really wasn't straightforward. I'm going to try to make it into a intelligible thing.

If there is a +3 charge and a -1 charge at a distance from one another, where to the right of these two charges would there be a point where the total electric field is zero?
+3 ---------- -1 ----------- P

Homework Equations


E=Qk/r^2



The Attempt at a Solution


I'm not sure if I did the right things but this is what I did:

I named the distance from +3 to P r1 and the distance from -1 to P r2.
If the total electric field must be zero, then I think that the electric field due to +3 must be equal but opposite to the one due to -1. Maybe?
So I put it like this:

E1=-E2
Q1K/r1^2 = -Q2K/r2^2
I canceled out the K.
And for Q1 I put the +3 charge. For Q2 I put the -1 charge.

(r2^2)*3=r1^2
r2=√(r1^2/3)
The question didn't ask from where would the distance be measured, so I picked from the -1 charge.
Would this be right?? Is Q only the magnitude?? Thank you!
 
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Yes it is the correct way. And you are always allowed to chose your coordinate system as you wish, it wouldn't change the result.

You could even go further, and simplify it, by saying the charges are a distance, d from each other, and that the distance from the -1 charge to P is r, then you have

3/(r+d)^2 = 1/r^2

Then you can solve it, and find, where the point P is relative to the distance between the two charges.
 
hjelmgart said:
Yes it is the correct way. And you are always allowed to chose your coordinate system as you wish, it wouldn't change the result.

You could even go further, and simplify it, by saying the charges are a distance, d from each other, and that the distance from the -1 charge to P is r, then you have

3/(r+d)^2 = 1/r^2

Then you can solve it, and find, where the point P is relative to the distance between the two charges.

Oh, okay! Thank you very much! :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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