Finding the point where the net electric field is zero

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SUMMARY

The discussion centers on determining the location of a point where the net electric field is zero between a +3 charge and a -1 charge. The solution involves setting the electric fields due to each charge equal in magnitude but opposite in direction, leading to the equation E1 = -E2. By substituting the known values and simplifying, the relationship between the distances from the charges to the point P can be expressed as 3/(r+d)^2 = 1/r^2, allowing for the calculation of the exact position of point P.

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Homework Statement


The question wasn't really written down. It was a question asked after an explanation, and it really wasn't straightforward. I'm going to try to make it into a intelligible thing.

If there is a +3 charge and a -1 charge at a distance from one another, where to the right of these two charges would there be a point where the total electric field is zero?
+3 ---------- -1 ----------- P

Homework Equations


E=Qk/r^2



The Attempt at a Solution


I'm not sure if I did the right things but this is what I did:

I named the distance from +3 to P r1 and the distance from -1 to P r2.
If the total electric field must be zero, then I think that the electric field due to +3 must be equal but opposite to the one due to -1. Maybe?
So I put it like this:

E1=-E2
Q1K/r1^2 = -Q2K/r2^2
I canceled out the K.
And for Q1 I put the +3 charge. For Q2 I put the -1 charge.

(r2^2)*3=r1^2
r2=√(r1^2/3)
The question didn't ask from where would the distance be measured, so I picked from the -1 charge.
Would this be right?? Is Q only the magnitude?? Thank you!
 
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Yes it is the correct way. And you are always allowed to chose your coordinate system as you wish, it wouldn't change the result.

You could even go further, and simplify it, by saying the charges are a distance, d from each other, and that the distance from the -1 charge to P is r, then you have

3/(r+d)^2 = 1/r^2

Then you can solve it, and find, where the point P is relative to the distance between the two charges.
 
hjelmgart said:
Yes it is the correct way. And you are always allowed to chose your coordinate system as you wish, it wouldn't change the result.

You could even go further, and simplify it, by saying the charges are a distance, d from each other, and that the distance from the -1 charge to P is r, then you have

3/(r+d)^2 = 1/r^2

Then you can solve it, and find, where the point P is relative to the distance between the two charges.

Oh, okay! Thank you very much! :)
 

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