Finding the Second Root of a Complex Number Equation

Click For Summary

Homework Help Overview

The problem involves finding the second root of a quadratic equation given one root as a complex number, specifically 4 + 5i. The equation is presented in the standard form x^2 + ax + b = 0.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the quadratic formula and the nature of complex roots, questioning whether the coefficients a and b are real numbers.

Discussion Status

Some participants have provided insights into the quadratic formula and its application to complex roots. There is recognition of the simplicity of the problem, but also an acknowledgment of potential assumptions regarding the nature of the coefficients.

Contextual Notes

There is uncertainty about whether the coefficients a and b are real, which could affect the nature of the second root.

Maatttt0
Messages
37
Reaction score
0

Homework Statement



One root of the equation x^2 + ax + b = 0 is 4 + 5i.

Write down the second root.

Homework Equations



N/a?

The Attempt at a Solution



My problem is it's a "write down" question which suggests no working required. This is probably so simple but I just don't know... I cannot do this even thought I know the later parts of the question. Thank you in advance ;)
 
Physics news on Phys.org
Write down the quadratic equation as you know it. The quadratic formula gives you two equations using one formula. What changes about the formula that gives you 2 separate solutions?
 
The plus or minus, so would it be 4 - 5i?
 
Yup! The quadratic formula gives solutions as

\[<br /> \frac{{ - b}}{{2a}} \pm \frac{{\sqrt {b^2 - 4ac} }}{{2a}}<br /> \]<br />

However, you can rewrite the quadratic formula by pulling out a -1 from the term in the square root to get

\[<br /> \frac{{ - b}}{{2a}} \pm i\frac{{\sqrt {4ac - b^2 } }}{{2a}}<br />

So you can identify the 4 and the 5 with the real and imaginary parts of the equation.
 
Hehe, thank you so much :)

I know it was rather simple but my mind just wouldn't trigger.

Ty again ;)
 
By the way, that answer is correct only if a and b are both real. If the problem doesn't specify that they are, then the other root could be any complex number.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
9
Views
2K
Replies
39
Views
6K
  • · Replies 14 ·
Replies
14
Views
2K