Finding the Sum of an Alternating Geometric Sequence

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The discussion focuses on finding the sum of an alternating geometric sequence with terms 30, -31, 32, and -32. The sequence can be separated into two parts, but the lengths differ, complicating the sum calculation. A general formula is proposed: for odd n (n=2m+1), the sum is 1/4(-3^(2m+1)+1), and for even n (n=2m), it is 1/4(3^(2m+1)+1). The combined formula for both cases is 1/4((-1)^n * 3^(n+1) + 1). Setting n=1 in this formula yields a sum of -1/2.
Sarah00
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Hi!

If I have a sequence that its first 4 terms are:

30, -31, +32, -32

The pattern is geometric sequence but has alternating signs..

How can I find its sum ..

I know it is composed of 2 sequences ..

However, when I try to separate the 2 sequences .. I get them of different "lengths"

In other words, it is (30+32+34) - (31+33) for 5 terms

but for 4 terms I get:
In other words, it is (30+32) - (31+33)How can I get general formula for both ..

(-1)k helps ! but how! and what about the number of termsThanks!
 
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Further to my previous post ..

screenshot_158.png
 
This is the book's answer:
screenshot_158.png
 
When ##n## is odd that is ##n=2m+1## you obtain ## \frac{1}{4}(-3^{2m+1}+1)##, when is even ##n=2m## you obtain ## \frac{1}{4}(3^{2m+1}+1)##. In order to obtain both you must have ## \frac{1}{4}((-1)^{n}3^{n+1}+1)## (this is obtained merging the two previous...)
 
Sarah00 said:
Further to my previous post ..

screenshot_158.png

If you set ##n = 1##, then your formula gives ##S = -1/2##
 
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