Finding the Third Side of a Triangle: 8 & 22

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For a triangle with sides measuring 8 and 22, the range for the third side is determined by the Triangle Inequality Theorem. The third side must be greater than the difference of the two sides (22 - 8 = 14) and less than their sum (22 + 8 = 30). This gives the range of 14 < x < 30. The correct answer to the multiple-choice options provided is A. Understanding these principles is crucial for solving similar geometry problems.
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[3.06] If two sides of a triangle are 8 and 22, what is the range of possibilities for the third side?
 
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First, this belongs in the homework help forum, someone will probably move it for you,

second: try drawing the triangle, with various angles between the two known sides, and see what sorts of values you can get for the length of the third side.

Edit:
Aha, someone moved it while I was typing.
 
oh, and third, please try to make the title a little more informative than just "help me".
 
stealthinstinct said:
[3.06] If two sides of a triangle are 8 and 22, what is the range of possibilities for the third side?

i tried drawing it, it is multiple choise, here are my options:


a. 14<x<30

b. 8<x<22




c. 4<x<18



d. 12<x<18
 
I think its A, 22-8 is 14... 22+8 is 30... none of the other ones make sense as possible answeres, am i right?
 
ok, i just submitted, i got the problem right, it was A... 300/300 points.. YEAH!
 
Well, one side of a triangle is a straight line and so is the shortest distance between the two points: if two sides of the triangle are 8 and 22, then the third side must be less than 8+ 22= 30. Other than that, I can't say.
 
stealthinstinct said:
[3.06] If two sides of a triangle are 8 and 22, what is the range of possibilities for the third side?
Check in your Geometry book for "Triangle Inequality Theorem". If a triangle has sides a, b, c; and if sides a and b are known, then this means a+b>c. Can you figure out the rest and apply the theorem?
 
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