Finding the total area of the shaded region.

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SUMMARY

The discussion centers on calculating the total area of a shaded region using integration techniques. The participant initially attempted to solve the problem by expressing the area as f(x) - g(x) and integrating, but questioned their results when the answer differed from the expected value of π/2. A suggestion was made to differentiate the result to verify correctness, along with a recommendation to use a trigonometric half-angle identity for integrating the squared cosine function.

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Homework Statement




http://img545.imageshack.us/img545/6260/hardproblem.png

Homework Equations



1. First I solved for y
2. I put it in the form f(x)-(g(x)
3. Then I integrated


The Attempt at a Solution



The answer in my book says it is ∏/2.

I don't think I'm integrating right. I end up with this towards the end

http://img15.imageshack.us/img15/2431/hardproblem3rdstep.png
 
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november1992 said:

Homework Statement




http://img545.imageshack.us/img545/6260/hardproblem.png
What shaded region? There is nothing shaded. What is the verbal description of the region?
november1992 said:

Homework Equations



1. First I solved for y
2. I put it in the form f(x)-(g(x)
3. Then I integrated


The Attempt at a Solution



The answer in my book says it is ∏/2.

I don't think I'm integrating right. I end up with this towards the end

http://img15.imageshack.us/img15/2431/hardproblem3rdstep.png
No, that is incorrect. To confirm this fact, differentiate your result. If you don't get the original integrand, that's a clue that you're on the wrong track.

There's a trig half-angle identity you can use to integrate that squared cosine.
 
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