Finding the velocity of a skier

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SUMMARY

The discussion focuses on calculating the northerly and easterly velocities of a kite skier moving at 25 m/s in the N 25° E direction, resulting in 10.6 m/s north and 22.7 m/s east using sine and cosine functions. The skier experiences an additional eastward acceleration of 2.0 m/s² for 1.8 seconds due to wind, which needs to be factored into the new resultant velocity calculation. The conversation emphasizes the importance of understanding vector components and their relationships in determining overall velocity.

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Problem Statement: 1.I'm asked to find the northerly and easterly velocity of kite skier. the skier is moving 25 ms^1 in the N 25degrre E direction.

2. Wind from the west makes the skier accelerate to the east at 2.0ms^1 for 1.8s CAlculate the new velocity.

3. Use the answer from (1) to calculate the size and direction of the new resultant velocity of the skier.
Relevant Equations: I used Sin and Cos for number 1

For number 1 I used the Sin and Cos of 25degrees to find the Northerly and easterly velocities. MY results are 10.6m s^1 Northerly and 22.7m s^-1 Easterly. SIn 25degrees= Vn/25 Vn= 25 Sin 25degrees = 10.6m s^1 N Cos 25degrees = Ve/25 25 Cos 25degrees=22.7m s^-1 E

For number 2 all I know is that we are given the acceleration and time.

Maybe it's not working because I've incorrectly solved for 1?

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Please show your diagram for part 1.
 
amazingphysics2255 said:
Problem Statement: 1.I'm asked to find the northerly and easterly velocity of kite skier. the skier is moving 25 ms^1 in the N 25degrre E direction.

2. Wind from the west makes the skier accelerate to the east at 2.0ms^1 for 1.8s CAlculate the new velocity.

3. Use the answer from (1) to calculate the size and direction of the new resultant velocity of the skier.
Relevant Equations: I used Sin and Cos for number 1

MY results are 10.6m s^1 Northerly and 22.7m s^-1 Easterly.
If 25 degrees E of N, which component would you expect to be the larger, E or N?
 
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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amazingphysics2255 said:
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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The angle between due north and the velocity vector is 25 degrees.
 
amazingphysics2255 said:
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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Right, but I am also trying to give you a way to check for yourself in future.
 
How does this help me solve my 3 questions?
 
amazingphysics2255 said:
How does this help me solve my 3 questions?
Doesn’t having it explained to you that your first answer was wrong help you get towards the right answer?
 
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