Finding the velocity of a skier

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The discussion focuses on calculating the northerly and easterly velocities of a kite skier moving at 25 m/s in a N 25° E direction. The initial calculations yield 10.6 m/s north and 22.7 m/s east using sine and cosine functions. A subsequent wind from the west accelerates the skier eastward at 2.0 m/s for 1.8 seconds, prompting a need to determine the new velocity. Participants express confusion about the expected magnitudes of the velocity components and the implications for future calculations. The thread concludes with a note that the original poster's adjustments to the content hindered further discussion.
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Problem Statement: 1.I'm asked to find the northerly and easterly velocity of kite skier. the skier is moving 25 ms^1 in the N 25degrre E direction.

2. Wind from the west makes the skier accelerate to the east at 2.0ms^1 for 1.8s CAlculate the new velocity.

3. Use the answer from (1) to calculate the size and direction of the new resultant velocity of the skier.
Relevant Equations: I used Sin and Cos for number 1

For number 1 I used the Sin and Cos of 25degrees to find the Northerly and easterly velocities. MY results are 10.6m s^1 Northerly and 22.7m s^-1 Easterly. SIn 25degrees= Vn/25 Vn= 25 Sin 25degrees = 10.6m s^1 N Cos 25degrees = Ve/25 25 Cos 25degrees=22.7m s^-1 E

For number 2 all I know is that we are given the acceleration and time.

Maybe it's not working because I've incorrectly solved for 1?

MENTOR NOTE: Content restored, thread locked.
 
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Please show your diagram for part 1.
 
amazingphysics2255 said:
Problem Statement: 1.I'm asked to find the northerly and easterly velocity of kite skier. the skier is moving 25 ms^1 in the N 25degrre E direction.

2. Wind from the west makes the skier accelerate to the east at 2.0ms^1 for 1.8s CAlculate the new velocity.

3. Use the answer from (1) to calculate the size and direction of the new resultant velocity of the skier.
Relevant Equations: I used Sin and Cos for number 1

MY results are 10.6m s^1 Northerly and 22.7m s^-1 Easterly.
If 25 degrees E of N, which component would you expect to be the larger, E or N?
 
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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amazingphysics2255 said:
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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The angle between due north and the velocity vector is 25 degrees.
 
amazingphysics2255 said:
They way you've phrased the question I'm assuming it's the opposite to what I've put. So If I was thinking East should be bigger than I'm probably wrong and It's North.
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Right, but I am also trying to give you a way to check for yourself in future.
 
How does this help me solve my 3 questions?
 
amazingphysics2255 said:
How does this help me solve my 3 questions?
Doesn’t having it explained to you that your first answer was wrong help you get towards the right answer?
 
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Thread locked, OP is changing the content without disclosing why making it difficult to respond.
 
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