The car passes point A with a speed of 25 m/s after which its speed is defined by V = (25-0.15s)m/s. Determine the magnitude of the car's acceleration when it reaches point B, where S = 51.5 m. (the max height of the hill is 16 m, and the function of the hill the car is on is y = 16 -(1/625)x^2. A intersects the axis at the furthest point from the origin in the positive direction. S (the Car) is left of A between A and B.)
The position and velocities given and the radius of curvature (rho) equation.
The Attempt at a Solution
I've solved this problem, that is, the magnitude of an and at. However, an is in terms of x because I can't figure out how to get an x range. I know if I had a "let x = #" I would plug it into the y = 16 -(1/625)x^2 and crunch it to get a Vy, so I'm stuck. Thanks in advance...