Finding the yearly income from energy in W

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AI Thread Summary
The discussion revolves around calculating the yearly income from the energy generated by falling water at Niagara Falls. The potential energy lost is 1 billion joules per second, equating to a power output of 1 billion watts or 1 million kilowatts. The correct method involves converting the power output into kilowatt-hours over a year and then multiplying by the industrial rate of 0.8 cents per kilowatt-hour. The initial calculations presented were incorrect due to a miscalculation in the conversion to kilowatt-hours. The final income calculation should reflect the accurate energy output multiplied by the rate over the total hours in a year.
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Homework Statement



Approximately 1.7*10^6 kg of water drops 60 m over Niagara Falls every second. 1*10^9 J of potential energy is lost every second by the falling water. If an electrical generating plant could convert all of the potential energy into electrical energy it would have a power output of 1*10^9 W. If the utility company sold this energy at an industrial rate of 0.8 cents per kW-hour, what would their yearly income be from this source (give your energy in dollars)?

Homework Equations



1 kW =1000 W
365 days=1 year
8760 hours = 1 year

The Attempt at a Solution



1*10^9 W -> 1*10^6 kW

1*10^6 kW * 60 sec/min * 60 min/hour = 3.6 *10^9

3.6 *10^9 * 0.008 = 2.88*10^7

2.88*10^7 * 8760 = 2.52*10^11

it says this is wrong. I have one shot left. what am I doing wrong?


 
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This bit is wrong..

1*10^6 kW * 60 sec/min * 60 min/hour = 3.6 *10^9

If the output is 1*10^6 kW then after one hour it has delivered 1*10^6 kWH. You only need to multiply that by the number of hours there are in a year and the price per kWH.
 
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