Finding total current for series capacitors

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Discussion Overview

The discussion revolves around finding the total current in a circuit with capacitors arranged in series. It includes considerations for both DC and AC circuits, as well as the implications of frequency on the calculations involved.

Discussion Character

  • Technical explanation, Conceptual clarification, Homework-related

Main Points Raised

  • One participant questions the relevance of finding total current for series capacitors in a DC circuit, suggesting that the question may be meaningless in that context.
  • Another participant states that for AC circuits, it is necessary to specify the frequency or frequencies of interest to accurately address the question.
  • A participant explains that the total current through series capacitors is the same as the current through each individual capacitor and provides a formula for calculating the combined capacitance of capacitors in series.
  • This participant also introduces the concept of reactance for capacitors and provides a formula for calculating current based on voltage and reactance.
  • A later reply expresses gratitude for the clarification and indicates that the original poster realized their oversight in applying the formula for current.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the applicability of the question for DC circuits, and there are differing views on the necessity of specifying frequency for AC circuits. The discussion remains unresolved regarding the implications of these factors.

Contextual Notes

The discussion highlights the dependence on circuit type (DC vs. AC) and the importance of frequency in calculations, which may not have been fully addressed by all participants.

jaredogden
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I guess the title basically explains it. I'm reading over some circuits and can't figure out how to find total current for a circuit with capacitors in series.
 
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For DC it's meaningless to ask the question. For AC you need to specific something about the frequency or frequencies of relevance.
 
The total current through series capacitors is the same as through each of them.

The combined capacitance of capacitors in series is:
fa34ce461e6988fd973081401cc9790c.png


So, if you calculate this to get the combined capacitance of the series capacitors, you can then regard the result as one capacitor.

The reactance X of a capacitor is:
331f118c5d84ff180213e4ed2a95674a.png


So, you can calculate the current from this formula:
Currrent = V / X
where V is the peak, or the peak to peak, or the RMS voltage of a sinewave. The current will then be the peak, peak to peak, or RMS value of the AC current.
 
Thanks Vk6kro. I actually finally figured it out I had the reactance but for some reason just wasn't thinking to use V/X I felt stupid once I realized that. Thanks again
 

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