jaredogden
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I guess the title basically explains it. I'm reading over some circuits and can't figure out how to find total current for a circuit with capacitors in series.
Finding total current for series capacitors
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jsgruszynski
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For DC it's meaningless to ask the question. For AC you need to specific something about the frequency or frequencies of relevance.
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The total current through series capacitors is the same as through each of them.
The combined capacitance of capacitors in series is:
So, if you calculate this to get the combined capacitance of the series capacitors, you can then regard the result as one capacitor.
The reactance X of a capacitor is:
So, you can calculate the current from this formula:
Currrent = V / X
where V is the peak, or the peak to peak, or the RMS voltage of a sinewave. The current will then be the peak, peak to peak, or RMS value of the AC current.
The combined capacitance of capacitors in series is:
So, if you calculate this to get the combined capacitance of the series capacitors, you can then regard the result as one capacitor.
The reactance X of a capacitor is:
So, you can calculate the current from this formula:
Currrent = V / X
where V is the peak, or the peak to peak, or the RMS voltage of a sinewave. The current will then be the peak, peak to peak, or RMS value of the AC current.
jaredogden
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Thanks Vk6kro. I actually finally figured it out I had the reactance but for some reason just wasn't thinking to use V/X I felt stupid once I realized that. Thanks again