Finding upper and lower bound superposition frequencies of ultrasound pulses

AI Thread Summary
Ultrasound pulses with a frequency of 1.000 MHz and a spatial length of 12 mm were analyzed, revealing that there are 8 complete cycles in each pulse. The time duration of the pulse was calculated as 8 microseconds, leading to the determination of the frequency range needed for superposition. The lower and upper bounds of the frequency range are centered around 1.000 MHz, with a total range of 125,000 Hz. This means the lower bound is approximately 937.5 kHz and the upper bound is about 1.0625 MHz. Understanding these bounds is crucial for accurately creating the ultrasound pulse.
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Homework Statement


Ultrasound pulses of with a frequency of 1.000 MHz are transmitted into water, where the speed of sound is 1500m/s . The spatial length of each pulse is 12 mm.

a) How many complete cycles are in each pulse?

b) What is the lower bound of the range of frequencies must be superimposed to create each pulse?

c)What is the upper bound of the range of frequencies must be superimposed to create each pulse?

Homework Equations


ΔX=ΔtV
f=1/T


The Attempt at a Solution



a) Δt= 12mm/1500 = 8 * 10^-6
T = 1/f
T = 1/10^6 = 10^-6

So... (8 * 10^-6)/(10^-6) = 8 full cycles in each pulse

b) and c) I have no idea... All I have is..

Δf = 1/Δt = 125,000 Hz.. How do I find the upper/lower bound?
 
Physics news on Phys.org
It looks like the range of frequencies will cover a 125,000 Hz range, centered on 1.000 Mhz. From that you can figure out the lowest and highest frequencies in the range.
 
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