Finding Values of r and q to Satisfy H

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Homework Help Overview

The problem involves determining values for r and q such that two vectors, X and Y, belong to a specified subset H of R^3 defined by the equation a + 2b - c = 0. The original poster expresses uncertainty about how to approach the problem, noting a lack of similar examples in their study materials.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the structure of the subspace H and its spanning family, while some participants suggest a more straightforward application of the subspace definition to find r and q.

Discussion Status

Participants are exploring different interpretations of the problem, with some providing guidance on how to apply the definition of the subspace to find the required values. There is no explicit consensus on the final values yet, but a productive direction has been established.

Contextual Notes

The original poster mentions being self-taught and struggling with the problem for an extended period, indicating a potential lack of resources or examples to draw from.

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Homework Statement



H is subset of R^3 dfined by H = {(a,b,c) element of R^3: a+2b-c = 0}. X=(r,1.2), Y =(1,2,q) are two vectors. Find the values r and q such that both X and Y belong to H

Homework Equations





The Attempt at a Solution


To be honest, I don't know where to start. I'm studying this by myself and the book doesn't have an example similar to this question. All that i know is that [1,2,-1] is a null space of H. This would help me find the spanning family for H: I can write a in term of b and c i.e a =-2b+c. So (a,b,c) = (-2b+c,b,c) = b(-2,1,0)+c(1,0,1)..therefore (-2,1,0) and (1,0,1) form a spanning family for H. How can I find r and q then? I'd appreciate your help.
Thanks.
 
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You are making this way too complicated. If X=(r,1,2) is an element of the subspace, then you want r+2*1-2=0, right? That's the definition of the subspace. And it's pretty easy to solve.
 
Dick said:
You are making this way too complicated. If X=(r,1,2) is an element of the subspace, then you want r+2*1-2=0, right? That's the definition of the subspace. And it's pretty easy to solve.

Thanks Dick.
So does that mean r+2-2 = 0, hence r=0 for vector X, 1+2*2-q=0, hence q =5 and for Y?
 
mccoy1 said:
Thanks Dick.
So does that mean r+2-2 = 0, hence r=0 for vector X, 1+2*2-q=0, hence q =5 and for Y?

It certainly does.
 
Dick said:
It certainly does.

Thank you, it's appreciated. I was stuck on this for 2 good hours.
 

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