Finding Vector Components of A and B in Spherical Coordinates

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SUMMARY

The discussion focuses on finding the vector components of vectors A and B in spherical coordinates. For part a, the correct approach involves using the dot product to determine the scalar projection of vector B onto vector A, which can then be converted into a vector by multiplying the scalar result with the unit vector of A. For part b, the vector component of B perpendicular to A can be found by subtracting the component of B in the direction of A from vector B itself. This method ensures accurate representation of both components in spherical coordinates.

PREREQUISITES
  • Understanding of vector operations, specifically dot product and cross product.
  • Familiarity with spherical coordinates and unit vectors.
  • Basic knowledge of vector decomposition techniques.
  • Ability to visualize vector components graphically.
NEXT STEPS
  • Study the properties of the dot product and how it relates to vector projections.
  • Learn about vector decomposition in spherical coordinates.
  • Explore graphical methods for visualizing vector components.
  • Practice problems involving vector components using both dot and cross products.
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on vector analysis and spherical coordinates, as well as educators looking for effective teaching methods for vector decomposition.

Tom McCurdy
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Homework Statement


I have a vector A and B in spherical coordinates, and I need to find:
  • part a) The vector component of B in the direction of A.
  • part b) The vector component of B perpendicular to A


Homework Equations


dot product
cross product

The Attempt at a Solution



Alright at my first look I saw vector component and I thought of the cross product which yields a vector result, but then I realized that it in no way tells us anything about B in the direction of A. So then dot product came to mind but that yeilds a scaler result. So I am kind of stumped as to where to start.

My only idea for part a was to take (A dot B)/vector A which would yield a vector result.
and I had no idea what to do for part b.
 
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What can you say about:
(vector B) minus (your answer to part a) ?
 
wouldn't you just get vector B pointing the other way

i am not sure what you are hinting at
 
Draw a picture... and maybe form dot and/or cross products with "(vector B) minus (your answer to part a)".
 
the thing is I still don't have an answer to a, so its hard for me to know what you mean
 
A dot B gives you a scalar - and this is the magnitude of the answer that you want in (a). But the direction is simply that of vector A. So, you can construct the vector component by simply multiplying this scalar by the unit vector along A.

As suggested by robphy, draw a diagram...everything will fall into place.
 
Tom McCurdy said:
the thing is I still don't have an answer to a, so its hard for me to know what you mean

I thought you had part a... or something close to it.
To make life easier, work with the unit vector along \vec A, namely \hat A = \frac{1}{A}\vec A.

As a simpler example, consider \hat A=\hat x.
How would you find the vector component of \vec B along the x-direction?
What can be said about the "remaining piece" in terms of the x-direction?
 

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