Finding Velocity in Spring Problem

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The discussion revolves around solving a physics problem involving energy conservation in a spring system. The user calculated the height (h1) using the formula h1 = Dsin(theta) and found it to be 0.579 m. However, they expressed uncertainty about their final velocity calculation, suspecting they might have set up the equation incorrectly. It was noted that the compression of the spring should be included in the calculations. The user plans to re-evaluate their approach to confirm if the compression was the only oversight.
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Homework Statement



314ealu.jpg


Homework Equations



K1 + Ug1 + Us1 = K2 + Ug2 + Us2

The Attempt at a Solution



Need to find h1, and that is h1 = Dsin(theta) = .92sin(39) = .579 m

.5mv1^2 + mgh1 + .5kx^2 = .5mv2^2 + mgh2 + .5kx^2

0 + mgh1 + .5kx^2 = .5mv2^2 + 0 + 0

1.7*9.8*.579 + .5*170*.18^2 = .5*1.7v2^2

12.40014 = .85v2^2

v2 = 3.8195 m/s

My answer is wrong apparently, not quite sure what I did wrong either as it seems all the work is right. I guess I set it up wrong, is it supposed to be mgh1 = .5mv2^2 + .5kx^2 ?
 
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Need to find h1, and that is h1 = Dsin(theta) = .92sin(39) = .579 m


to find h1 use L = (0.92 + 0.18)
 
rl.bhat said:

Need to find h1, and that is h1 = Dsin(theta) = .92sin(39) = .579 m


to find h1 use L = (0.92 + 0.18)

Ah I see now, I was just using the .92 and not utilizing the compression. I'll try it again and see if I get it correct. Is that my only error then?
 
I think so.
 
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