Finding Velocity Zero: Solving a High School Calculus Problem

  • Thread starter Thread starter undrcvrbro
  • Start date Start date
  • Tags Tags
    High school School
Click For Summary
SUMMARY

The discussion centers on solving a high school calculus problem involving the function y = (x^3) - (9x^2) + 15x to find when the velocity v equals zero. The derivative of the function, v = y' = (3x^2) - (18x) + 15, was correctly identified. The equation 3x^2 - 18x + 15 = 0 was established to find the critical points where velocity is zero. Factorization of this quadratic equation is the next step to determine the specific values of x.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives
  • Familiarity with polynomial functions and their properties
  • Knowledge of solving quadratic equations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Practice solving quadratic equations through factorization
  • Explore the concept of derivatives in calculus
  • Learn about critical points and their significance in motion analysis
  • Study the application of calculus in physics, particularly in kinematics
USEFUL FOR

High school students studying calculus, educators teaching calculus concepts, and anyone interested in applying calculus to real-world problems in physics or engineering.

undrcvrbro
Messages
133
Reaction score
0
[SOLVED] high school calc problem

Homework Statement


If an object moves along the y-axis (marked in feet) so that its position at time x (in seconds) is given by the indicated function; y= (x^3)-(9x^2)+15x;
Find when v=0


Homework Equations


v=y prime, and i already have found y prime to be (3x^2)-(18x)+15


The Attempt at a Solution


I checked the selected answers in the back of the book and did a little plug and chug and called it a day...:blushing:.. haha. I'm assuming there's a more relevant process so any help is mucho appreciated. thanks.
 
Physics news on Phys.org
if v=y'

then shouldn't v=3x^2-18x+15

when v=0

3x^2-18x+15=0


try some factorisation
 
wow...thank you

haha I am not sure how i didn't see that. I really didn't think anyone would answer. I believe I've just found a new home for homework help...and considering I will be going into chemE next next year in college, I should be revisiting many of times!

haha thank you a lot!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K