Finding Voltages at V1, V2, and V3 using Node Analysis

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Discussion Overview

The discussion centers around finding the voltages at nodes V1, V2, and V3 in a circuit using node analysis. It involves applying node analysis techniques to derive equations based on circuit components and current sources.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents equations derived from node analysis for the voltages V1, V2, and V3, expressing concern about obtaining a negative voltage (V3 = -26V) despite a positive voltage source (12V) in the circuit.
  • Another participant asserts that there are constant current sources in the circuit, suggesting that the voltage source is not the only contributor to the current, which may affect the voltage calculations.
  • A third participant expresses appreciation for the input received, indicating engagement with the discussion.

Areas of Agreement / Disagreement

The discussion includes differing perspectives on the contributions of various sources in the circuit, indicating that multiple views remain regarding the analysis and interpretation of the results.

Contextual Notes

Participants have not resolved the implications of the negative voltage result or fully clarified the role of the constant current sources in relation to the voltage source.

tanky322
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Homework Statement


Find the voltages at V1 V2 & V3 in the attached circuit using node analysis.



Homework Equations



Node analysis

The Attempt at a Solution



I came up with a few equations for the variables:

V1(.5+1)-12(.5)=5
V2(.333+.25)-V3(.25)=3
V3(.25)-V2(.25)=-5

Solving I get V1:7.33V
V2:-6V
V3:-26V
I think I did it right but i don't see how i can get -26V when there's only 12 to begin with??

Andrew
 

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No mistakes alright.
 
The voltage source is not the only source of current.
There are constant current sources involved in the circuit as well. So there would be situations of V= I(current from voltage source + current from constant current source)R.
 
Sweet! thanks allot!
 

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