Finding volume using integration

Click For Summary
SUMMARY

The discussion centers on calculating the volume of a solid formed by rotating the area between the curves defined by the equations x=y² and x=1 about the line x=1. The correct volume formula is pi*(1-y²)², which differs from the incorrect formula pi-pi*y⁴ proposed by the user. The discrepancy arises from misunderstanding the method of rotation; the appropriate method for this problem is the disk method, which involves integrating the area of circular disks perpendicular to the axis of rotation.

PREREQUISITES
  • Understanding of integration techniques in calculus
  • Familiarity with the disk method for volume calculation
  • Knowledge of the equations of curves and their graphical representation
  • Ability to set up and evaluate definite integrals
NEXT STEPS
  • Study the disk method for calculating volumes of solids of revolution
  • Learn how to derive volume formulas from the area between curves
  • Practice problems involving rotation about vertical lines
  • Explore the shell method as an alternative for volume calculations
USEFUL FOR

Students studying calculus, particularly those focusing on volume calculations of solids of revolution, as well as educators seeking to clarify integration techniques.

theBEAST
Messages
361
Reaction score
0

Homework Statement


Given x=y^2, x=1 what is the area of the solid when the area between the two curves is rotated about x=1.

The Attempt at a Solution


I attached my solution and according to the answer key my area formula (pi-pi*y^4) is wrong. Instead they have pi*(1-y^2)^2. Can anyone explain why my area formula is wrong? I thought that it was the area of the upper boundary curve minus the area of the lower boundary curve...
 

Attachments

  • photo (1).jpg
    photo (1).jpg
    26.9 KB · Views: 491
Physics news on Phys.org
theBEAST said:

Homework Statement


Given x=y^2, x=1 what is the area of the solid when the area between the two curves is rotated about x=1.

The Attempt at a Solution


I attached my solution and according to the answer key my area formula (pi-pi*y^4) is wrong. Instead they have pi*(1-y^2)^2. Can anyone explain why my area formula is wrong? I thought that it was the area of the upper boundary curve minus the area of the lower boundary curve...
What method are you trying to use? Is it disks? ... or is it shells?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
4
Views
3K
Replies
11
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K