Finding x in Parallel Lines Geometry Problem

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The geometry problem involves finding the value of x in a scenario with parallel lines, leading to an equation that simplifies to x = 2°. However, the provided answer choices include degrees and minutes, which raises confusion among participants. There is speculation about a possible error in the textbook or a typo in the problem's diagram. Some users express skepticism about the authenticity of the problem, suggesting it may be a joke or poorly constructed. The discussion remains open for further insights or alternative solutions.
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Homework Statement


Find x. L1 and L2 are parallel

ex79.png

choices:
a)2°40'
b)2°30'
c)2°45'
d)2°15'
e)2°20'

Homework Equations


Σleft∠ = Σright∠

The Attempt at a Solution


2x+1+4x-1+4x-1 = 2x-1+2x+4+3x+2
10x-1=7x+5
3x=6
x=2°

Not sure how the answers include minutes '

Maybe I'm overlooking something?
 

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I get the same result. Maybe an error in the book.
 
Yeah, that's what I think too. I'll leave this open just in case anybody has anything to add. Maybe another way of solving?
 
Quite possibly they made a typo when labelling the figure. You might be able to make a simple change to one of the coefficients or constants in the diagram to have it give their desired answer. :smile:
 
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Is this for real? I've seen other problems with a similar sort of handwriting style, and wrong answers which are said to be from the mysterious "book." So what exactly is the "book?" and why do people post this sort of thing? Sorry if I am too cynical, but I could almost believe this is some kind of joke.
 
Lol. I felt doubt about this because most of the problems i have solved had a correct answer in the choices.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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