Finding yield stress with only modulus of elasticity and Poisson's ratio?

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SUMMARY

Determining the yield stress of aluminum solely from its modulus of elasticity (E = 70 GPa) and Poisson's ratio (v = 0.3) is not feasible without additional information. The discussion highlights the application of Hooke's Law to relate stress and strain, but the yield stress, typically around 270-275 MPa for aluminum, is essential for solving structural problems. The user seeks assistance in calculating the minimum aluminum area required to support a 10 Newton load at a height of 1 meter, emphasizing the need for yield stress in their calculations.

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leoflc
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Is it possible to find the yield stress of a material with only modulus of elasticity and Poisson's ratio?

I was given a problem that:
What is the min. aluminum needed to support a block (10 Newton) to 1 meter high? E=70GPa and v=0.3 are the only given aluminum properties.

I would know how to solve it if I knew the yield stress.
Can anyone give me some help?

(I know the yield stress for Al is usually around 270-275, but let's pretend we don't know that).

Thanks a lot!
Leo

-----------------------------------
This is what I have so far:
use Hooke's Law for strain x, y, and z.
stress x = stress z = 0; stress y is in the vertical direction.
strain x = strain z = (-v*stress_y)/E

and I'm stuck...

Thanks.
 
Last edited:
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I would use Area=(PL)/(Epsilon*E)

Hope that helps
 
EQ said:
I would use Area=(PL)/(Epsilon*E)

Hope that helps

Thanks for the reply.
I might be missing something, but I don't know how to get the strain "Epsilon".
 
What application is the problem centered around? A beam? A column? The way you have things worded here it's impossible to help you with your question.
 

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