Finite and infinitesimal Rotations

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Josh1079
Messages
45
Reaction score
0
Hi,

I'm not sure about where I should post this question, so sorry in advance if I posted it in the wrong place.

My question is basically this screenshot. So I really have some difficulty in understanding the two equations. I mean how can it not be equal? I understand that rotations are non-commutative, but I really don't see why mathematically these two lines are not equal. Doesn't that violate the properties of matrix exponentials?

Thanks!

blank.png
 
Physics news on Phys.org
In general, if ##A## and ##B## are non-commuting operators, ##e^{A+B} \neq e^A e^B##. You can see this most easily by expanding each side in a Taylor series. The general solution is known as the Baker-Campbell-Hausdorff formula.

EDIT: actually, probably the easiest way to see this is to note that ##e^{A+B}=e^{B+A}## but ##e^A e^B \neq e^B e^A## for noncommuting ##A## and ##B##.
 
  • Like
Likes   Reactions: mathwonk
Ah...I see that now...didn't think it carefully enough

Thanks TeethWhitener!