Finite and infinitesimal Rotations

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SUMMARY

The discussion centers on the mathematical properties of finite and infinitesimal rotations, specifically addressing the non-commutativity of operators in the context of matrix exponentials. It is established that for non-commuting operators A and B, the equation e^(A+B) does not equal e^A * e^B, as demonstrated through the Taylor series expansion. The Baker-Campbell-Hausdorff formula provides the general solution to this issue, highlighting the distinction between the commutative property of the exponential function and the non-commutative nature of the operators involved.

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  • Understanding of matrix exponentials
  • Familiarity with non-commuting operators
  • Knowledge of Taylor series expansions
  • Awareness of the Baker-Campbell-Hausdorff formula
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Josh1079
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Hi,

I'm not sure about where I should post this question, so sorry in advance if I posted it in the wrong place.

My question is basically this screenshot. So I really have some difficulty in understanding the two equations. I mean how can it not be equal? I understand that rotations are non-commutative, but I really don't see why mathematically these two lines are not equal. Doesn't that violate the properties of matrix exponentials?

Thanks!

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In general, if ##A## and ##B## are non-commuting operators, ##e^{A+B} \neq e^A e^B##. You can see this most easily by expanding each side in a Taylor series. The general solution is known as the Baker-Campbell-Hausdorff formula.

EDIT: actually, probably the easiest way to see this is to note that ##e^{A+B}=e^{B+A}## but ##e^A e^B \neq e^B e^A## for noncommuting ##A## and ##B##.
 
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Ah...I see that now...didn't think it carefully enough

Thanks TeethWhitener!
 

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