Finite well penetration depths dependence on Well Length

PsychonautQQ
Messages
781
Reaction score
10
So in the infinite well Energy is proportional to 1/L^2, so I'm assuming in the finite well there is some sort of similar relation. So as the L decreases, the energy increases, so the wavelength decreases. Decreasing the wavelength means more energy, so it should penetrate further, but also if you draw the situation a smaller wavelength will make it penetrate less far, although the well also is getting smaller so blahh I'm trying to figure out how all this adds up. Thanks!
 
Physics news on Phys.org
PsychonautQQ said:
but also if you draw the situation a smaller wavelength will make it penetrate less far

What do you mean by this? I don't think it's correct.

I suggest you actually work through the solution of the finite square well and see how the penetration length of the ground state wave function depends on L.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Back
Top