Firing a spherical bullet into a watertank

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SUMMARY

The discussion focuses on the physics of a spherical bullet fired horizontally into a watertank, specifically addressing the non-constant acceleration experienced by the bullet. The retarding force acting on the bullet is defined by the equation F = -k · v, leading to a non-constant acceleration described by a = - (k/m) · v. The differential equation m · x'' - k · x' = 0 is established for solving the bullet's trajectory, although the user expresses difficulty in integrating due to the dependency of acceleration on velocity rather than time.

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TheMan112
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I've got a problem, involving non-constant acceleration:

If we fire a spherical bullet horizontally into a watertank, how far will the bullet traverse?

I've figured as much that a spherical bullet provides a retarding force:

F = -k \cdot v where k is a constant.

This should provide the following non-constant acceleration due to Newtons 2nd law.

a = \frac{F}{m} = - {\frac{k v}{m}}

I'm thinking I should integrate two times over a(t) to get an expression for x(t), but since "a" is proportional to v(t) and not directly to t, I don't know how to do it without getting a recursive expression.
 
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The differential equation to solve is:

m \ddot{x} - k \dot{x} = 0

And solutions are fairly straightforward to find.
 
you already posted this in HW-section.
 
Yes, my apologies. I started this thread before I noticed one should ask such questions i the HW-section. I'm going to post my reply to Andy there, you may remove this thread.
 
TheMan112 said:
Yes, my apologies. I started this thread before I noticed one should ask such questions i the HW-section. I'm going to post my reply to Andy there, you may remove this thread.

It's ok, threads are often moved to the correct place after awhile. Just wanted to draw your attention to this :-)
 

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