So, let's take the following:
[tex]Ay'+By=C[/tex]
I know its solution is: [tex]\frac{C}{B}(1-e^{-t\frac{B}{A}})[/tex]
For the homogenous part:
[tex]Ay'+By=0[/tex]
Characteristic equation is:
[tex]Ak+B=0[/tex]
[tex]k=-\frac{B}{A}[/tex]
So the solution for the homogenous part is:
[tex]y=e^{-t\frac{B}{A}}[/tex]
Now, from what I have read about variation of parameters, there is a function v such that:
[tex]Y=vy[/tex]
[tex]Y'=v'y+vy'[/tex]
So, would that be:
[tex]vBe^{-t\frac{B}{A}}=Y[/tex]
[tex]v'Be^{-t\frac{B}{A}}-v\frac{B^2}{A}e^{-t\frac{B}{A}}=Y'[/tex]
Err... Correct?