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## Homework Statement

The coefficient of the term (x−π)

^{2}in the Taylor expansion for f(x)=cos(x) about x=π is:

## Homework Equations

##cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \frac{x^8}{8!}...##

## The Attempt at a Solution

Unless my taylor series for cosine is incorrect, I'm not seeing any (x-π)

^{2}term. What am I missing here? I see that the 2nd term is a squared term and that the coefficient is -1. Is that the answer?