Undergrad Frcf= reactive centrifugal force...Frcf= -mv2/R

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SUMMARY

The discussion centers on the concepts of inertial and reactive centrifugal forces in fluid dynamics, specifically referencing the balance of forces in rotating and inertial frames. The key equation presented is Frcf = mv²/R, where Frcf represents the reactive centrifugal force. The conversation highlights the distinction between Newton's third law pairs and the force balance described by Newton's second law, clarifying that these forces do not balance each other but rather describe different interactions in fluid mechanics.

PREREQUISITES
  • Understanding of Newton's Laws of Motion, particularly the second and third laws.
  • Familiarity with fluid dynamics concepts, including pressure gradients and force balances.
  • Knowledge of inertial and non-inertial reference frames.
  • Ability to interpret and manipulate equations related to centripetal and centrifugal forces.
NEXT STEPS
  • Study the derivation and applications of the equation Frcf = mv²/R in fluid dynamics.
  • Explore the implications of Newton's third law in non-inertial frames of reference.
  • Investigate the role of pressure gradients in fluid flow and their relationship to centrifugal forces.
  • Learn about the differences between inertial and reactive centrifugal forces in various fluid dynamics scenarios.
USEFUL FOR

This discussion is beneficial for fluid dynamics engineers, physicists, and students studying mechanics, particularly those interested in the behavior of fluids in rotating systems and the forces acting on them.

Aeronautic Freek
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Pressure gradient normal to the local flow direction balance the centrifugal force associated with the curvature of flow..

Which centrifugal force inertial or "reactive" centrifugal force?
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Aeronautic Freek said:
Pressure gradient normal to the local flow direction balance the centrifugal force associated with the curvature of flow..

Which centrifugal force inertial or "reactive" centrifugal force?
View attachment 264265
There is no centrifugal force in your diagram.
 
A.T. said:
There is no centrifugal force in your diagram.
That tell Doug Mclean who write this in his book...
 
Aeronautic Freek said:
That tell Doug Mclean who write this in his book...
He didn't ask about the centrifugal force, you did.
 
A.T. said:
He didn't ask about the centrifugal force, you did.
this is text from his book:
"Pressure gradient normal to the local flow direction balance the centrifugal force associated with the curvature of flow.. "
 
Aeronautic Freek said:
this is text from his book:
"Pressure gradient normal to the local flow direction balance the centrifugal force associated with the curvature of flow.. "
The diagram apparently shows the inertial frame where there is no inertial centrifugal force on the fluid piece. The text seems to talk about a rotating frame where the centripetal net pressure force is balanced by an inertial centrifugal force.
 
A.T. said:
The diagram apparently shows the inertial frame where there is no inertial centrifugal force on the fluid piece. The text seems to talk about a rotating frame where the centripetal net pressure force is balanced by an inertial centrifugal force.
yes but you said that inertial centrifugal force is not pair(balance) to centripetal force
 
Aeronautic Freek said:
yes but you said that inertial centrifugal force is not pair(balance) to centripetal force
You are confusing Newtons 3rd Law pair with force balance in Newtons 2nd Law.
 
Aeronautic Freek said:
yes but you said that inertial centrifugal force is not pair(balance) to centripetal force
Third law pairs always act on different objects so they never balance each other. “Pair” relates to the third law and “balance” relates to the second law, so “pair(balance)” is kind of a contradiction.
 
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From the non-inertial frame of reference of an observer moving with the parcel of fluid, the centrifugal force is directed to the outside of the arc, and the force balance reads: $$P_{outside}A-P_{inside}A-F_c=0$$where $$F_c=m\frac{v^2}{R}$$with R representing the radius of curvature of the arc.
 
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  • #11
Chestermiller said:
From the non-inertial frame of reference of an observer moving with the parcel of fluid, the centrifugal force is directed to the outside of the arc, and the force balance reads: PoutsideA−PinsideA−Fc=0where Fc=mv2Rwith R representing the radius of curvature of the arc.
Thanks.
How you would write equation for inertial frame?

(Pout - Pin) x A = Frcf ?

Frcf= "reactive centrifugal force"...Frcf=mv2/R
 
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  • #12
Aeronautic Freek said:
Thanks.
How you would write equation for inertial frame?

(Pout - Pin) x A = Frcf ?

Frcf= "reactive centrifugal force"...Frcf=mv2/R
The 2nd Law equation for the parcel of fluid in the inertial frame would be:

(Pout - Pin) x A = Fcp

Fcp= "net centripetal force"...Fcp=mv2/R

The equation for Frcf that the parcel exerts on the neighboring parcels would be:

Frcf = -Fcp
 
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