Fluid Dynamics-D'Alembert's paradox

  • Context: Graduate 
  • Thread starter Thread starter hhhmortal
  • Start date Start date
  • Tags Tags
    Fluid Paradox
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 4K views
hhhmortal
Messages
175
Reaction score
0
Hi, I'm trying to prove D'alembert's paradox, but considering a nonviscous, irrotational flow of a fluid around a cylinder.

I used the following webpage to help me, which was very good, but I got to a part where I can't seem to solve, perhaps cause my maths needs some brushing up.

http://galileo.phys.virginia.edu/classes/311/notes/fluids1/fluids11/node19.html


It's on Equation (2.38). How do you get this from Eq 2.36 and Eq 2.37 ?

What component of velocity is being used on Eq 2.38?


Thanks.
 
Physics news on Phys.org
At the surface of the cylinder (stated measurement point)

R = r so substituting

The radial velocity (cosine term) is zero.

So total velocity is given by tangential velocity (sine term) alone

substitute R = r and square and you have your next equation (2.38)
 
Last edited:
Note - D'Alembert's paradox relies on a specific flow pattern in a fluid with zero viscosity. With zero viscosity, there's no interaction between adjacent "streamlines" so flow patterns aren't determinate. An alternate, but just as valid flow pattern would consists of a long rectangle of fluid flowing at the same speed as the cylinder, with no interaction of the surrounding fluid. It all depends on the initial state of the fluid. It's not clear to me, how any mathematical model can be made to predict a flow in fluid with zero viscosity.