I was searching the answers for the same question and came across ur question posted... i cud not find very clear answers anywer..
but i wud lik 2 share wat i guess.. i don't know whether my guess is right...
consider a falling object.. the object loses its pot energy and gains KE to reach the Earth surface... when this energy cons is applied to a fluid flow, wat we have is a Bernoulli eqn
3 forms of energy will be considered and the reasons why they are considered will be stated...
Pressure energy:
lets say, a volume of fluid is at rest... but this does not mean that there is no movement of molecules inside it... this volume has some def temp... dep on the temperature, there is random motion of molecules inside that bulk volume of fluid.. these molecules hit the surface and thus exert some pressure on it.. this is static pressure
Kinetic energy:
when the energy due to the random motion of molecules (internal energy) could be converted into kinetic energy, that is, orienting the random motion of molecules in a definite direction, the fluid is said to flow in that particular direction... this energy conservation is explained in Bernoullis eqn... but note that this eqn omits viscous, thermal effects in the flow
so when a part of this pressure energy is converted into K.E., fluid flows.. it is difficult to imagine that all this Press Energy is converted into K.E... bcoz, atleast few molecules would randomly move and hit the surface
Gravitational Potential energy:
similarily to any other object at height, fluid(air) also possesses grav P.E... this is what we express as rho*g*h(similar to m*g*h; but here we consider energy/unit volume)... let's consider 2 pts A and B in a flow with a height diff 'h'... we know atm P dec with alt.. So there is going to be a P diff now... hence there is a flow... At A, the grav Potential is g*h2 (rho is not considered since we are talking abt incomp form of Benoullis eqn; that's we cannot consider flows/convectional cycles in atm - because here density changes with alt) and similarily at B.. we can understand that the diff is goin to be much smaller as long as the flow is between closer vertical dist...
as long as the fluid flow occurs at a level surface, gravitational effects get canceled on applying Bernoulli eqn to the flow
when static P is always due to gravity, we cannot expect it to be equal in all radial directions when we consider the flow inside a circular pipe... so these 2 are diff... but, as we connect the static and pitot tubes to a manometer, we calculate the P diff by using gravity effect [since we use the formula P=rho*g*(h2-h1)].. this does not mean that the static pressure is actually due to gravity.. we just apply hydrostatic pressure principle to find out the actual static/total pressure
Most of the above is what i assume.. if wrong, feel free to point the mistakes