Fluid mechanics civil engineering

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SUMMARY

The discussion centers on calculating the force exerted on a hinged door in a tank with an inclined wall at a 45-degree angle. The specific gravity of sea water is given as 1.1, and the user calculates the force using the formula F = density * gravity * sin(angle) * Area * height, arriving at a force of 10.789 kN. However, there is confusion regarding the problem statement, as it references the force due to oil while only providing the specific gravity of sea water. Additionally, the validity of using a uniform depth for the entire door is questioned.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically hydrostatic pressure.
  • Familiarity with the concept of specific gravity and its application in fluid calculations.
  • Knowledge of trigonometry, particularly sine functions in relation to inclined surfaces.
  • Proficiency in applying formulas for calculating forces on submerged surfaces.
NEXT STEPS
  • Study the principles of hydrostatic pressure in fluids, focusing on varying depths.
  • Learn about the calculation of forces on inclined surfaces in fluid mechanics.
  • Explore the differences between specific gravity and density in fluid applications.
  • Investigate the effects of different fluid types (e.g., oil vs. water) on force calculations.
USEFUL FOR

Civil engineers, fluid mechanics students, and professionals involved in designing and analyzing structures with fluid interactions will benefit from this discussion.

Mikee Carlos
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Thread moved from the technical forums, so no HH Template is shown.
20160430_1951154.jpg
As shown in the attached image, a tank has an inclined wall at an angle of 450 to the horizontal. On this wall, there is a 1m square door that is hinged at A and has a simple latch at B. The distance between A and the free surface of sea water measured along the inclined wall is 2 m. (Specific gravity of sea water sg = 1.1). Calculate the force F on the door due to the oil
MY WORKING OUT could anyone pls help check if i am right :) P=F/A SO F=PA than F=densitygravitysin(angle)Areaheight now in order to find the height cause it's inclined i did sin 90/2=sin45/x cross multiply to get x-1.414 back to the formula 1100*9.81*sin45*1m^2*1.414 and i got 10.789kN as my force
 
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Hello Mikee, :welcome:

I find the problem sattement confusing: it asks for
Mikee Carlos said:
the force F on the door due to the oil
but it only gives the specific gravity of sea water. Why ? Where is the sea water ?
Your calculation also seems unlikely to me: you use 1.41 m (the depth of point A) as the depth for every point on the door ?
 
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