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## Homework Statement

A cork is held at the bottom of a bucket of

water by a piece of string. The actual depth

of the cork is 0.713786 m below the surface of

the water.

If the density of the cork is 157 kg/m3

and the volume of the cork is 3 cm3

, then what is the tension in the string? The acceleration

of gravity is 9.8 m/s

2

. Assume the density of

water is 1000 kg/m3

.

## Homework Equations

d= m/v Fb= weight of displaced fluid

## The Attempt at a Solution

The tension should be the force required to keep it in equilibrium...

using d=m/v, into dv = m (1000)(0.03) = 30 kg (mass of displaced water)(9.8)

weight of displaced water = Fb = 294 N

using dv = m again for the cork. (157)(0.03) = 4.71 kg (9.8) = 46.158 N

294 - 46.158 = 247.842 N .

Its a multiple choice answer and the choices are either that number but the decimals in the wrong place (all the answers are smaller), or 0.0123921 N.

maybe I'm supposed to use the depth and P=pgh somehow if that other numbers right, but i'm not sure how it would apply to this problem.