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Fluids Problem - Atmospheric Tank Pressure Vent

  1. Jul 10, 2013 #1
    1. The problem statement, all variables and given/known data
    Theres a atmospheric tank with a goose neck vent on the top and also an inlet pipe [a diameter 2 inch schedule 40] on the top. There is a compressed air line [from a 50 psi compressor] going into the inlet. The pressure inside the tank should not be above 2 psi. Size the diameter of the goose neck vent.

    Inlet:
    P = 50 psi
    Dinner = 2.07 inches
    ρ = 4.32 lb/ft^3

    Goose Neck Vent:
    P = 2 psi
    Dinner = ???


    2. Relevant equations
    Bernoulli's
    0.5ρV2 + P = 0.5ρV2 + P
    Q = V*A [volumetric flow rate]
    V*A = V*A [in = out]

    3. The attempt at a solution
    I assumed I could use bernoullis to find the V out from the compressed air line. [Pinside = 50, Poutside = 0 [atmsophere], Vin = 0, Vout=?]
    I got a Velocity of 68.31300511 ft/s

    From that and the cross sectional area of the 2.07in pipe I got a Q of 95.79056195 CFM.

    Next I moved onto the tank. I substituted
    VinAin/Aout = Vout into Bernoulli's and Solved for Aout.
    Aout = sqrt( Q2 / (Vin2 - 2*ΔP/ρ)

    Problem is I ended up getting the same cross sectional area as the inlet. I'm not sure where I went wrong. Perhaps incompressible flow? I appreciate any help.
     
  2. jcsd
  3. Jul 10, 2013 #2

    SteamKing

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    What's wrong with having an inlet and a vent with the same area?
     
  4. Jul 10, 2013 #3
    Nothing. But that doesn't satisfy the problem statement or make sense with my numbers.

    if Qin = Qout
    VA in = VA out
    and therefore Vin = Vout

    if this is true, according to Bernoulli's there would be no pressure change. My Pin and Pout are different. they need to be according to the problem statement. The ΔP should equal the 2 psi, if I'm not mistaken?
     
  5. Jul 10, 2013 #4

    SteamKing

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    If you are trying to maintain less than 2 psi pressure differential above atmospheric, then it seems your chosen method of solution is somewhat simplified.

    I think you are ignoring the change in pressure inside the tank as air is added from the 50 psi source. It seems that there should be an additional relation such that:

    net mass of air added to the tank = mass of air flowing in - mass of air flowing out of the vent

    The net mass of air added must be less than the amount of air which would produce a rise of 2 psi inside the tank above atmospheric. The vent would be sized to allow enough air to flow out so there would not be a buildup of additional air in the tank.

    When the air starts to flow from the 50 psi source, compressibility must be checked before assuming that Bernoulli applies.
     
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