Flux density and Divergence of Electric field

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Flux density is defined as the amount of electric flux passing through a unit area, while divergence measures the rate at which electric field lines spread out from a point in space. The discussion clarifies that flux density can be understood as electric field per unit area vector. Divergence is specifically defined as flux per unit volume, indicating a distinction between the two concepts. Overall, the participants agree that flux density and the divergence of the electric field are different quantities.
Shreya
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Homework Statement
Is flux density same as divergence of electric field
Relevant Equations
Div E = (lim as V tends to zero) of (1/V) E*dS
V is volume
I think Flux density is flux/Volume.
Or is it flux/ Area
Please be kind to help
 
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Divergence is defined as flux per unit volume.
 
Thanks a lot, Gordianus!
Gordianus said:
Divergence is defined as flux per unit volume
I think flux density is electric field / unit area vector...
So flux density and divergence of E are different,right?
 
Last edited:
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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